718 Maximum Length of Repeated Subarray
1. Question
Given two integer arraysA
andB
, return the maximum length of an subarray that appears in both arrays.
Example 1:
Input:
A: [1,2,3,2,1]
B: [3,2,1,4,7]
Output: 3
Explanation:
The repeated subarray with maximum length is [3, 2, 1].
Note:
1 <= len(A), len(B) <= 1000
0 <= A[i], B[i] < 100
2. Implementation
(1) DP
思路: 这题其实和求Longest Common Substring是一样的,所以可以直接套用模板写
class Solution {
public int findLength(int[] A, int[] B) {
int m = A.length;
int n = B.length;
int[][] dp = new int[m + 1][n + 1];
int maxLen = 0;
for (int i = 1; i <= m; i++) {
for (int j = 1; j <= n; j++) {
if (A[i - 1] == B[j - 1]) {
dp[i][j] = 1 + dp[i - 1][j - 1];
maxLen = Math.max(maxLen, dp[i][j]);
}
}
}
return maxLen;
}
}
3. Time & Space Complexity
DP:时间复杂度O(n), 空间复杂度O(n)
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