264 Ugly Number II
264. Ugly Number II
1. Question
2. Implementation
class Solution {
public int nthUglyNumber(int n) {
int factor2 = 2, factor3 = 3, factor5 = 5;
int index2 = 0, index3 = 0, index5 = 0;
int min = Integer.MAX_VALUE;
int[] dp = new int[n];
dp[0] = 1;
for (int i = 1; i < n; i++) {
min = Math.min(factor2, Math.min(factor3, factor5));
dp[i] = min;
if (min == factor2) {
factor2 = 2 * dp[++index2];
}
if (min == factor3) {
factor3 = 3 * dp[++index3];
}
if (min == factor5) {
factor5 = 5 * dp[++index5];
}
}
return dp[n - 1];
}
}3. Time & Space Complexity
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